Java Extracting only first Integer value from String

Here is the new java function that extracts the 1st Integer value from String:
String s = new String("Eric Mariacher 1965 AoxomoxoA 1967 Cowabunga 2009 ");
Matcher matcher = Pattern.compile("\\d+").matcher(s);
matcher.find();
int i = Integer.valueOf(matcher.group());

Here is the old java function that extracts the 1st Integer value from String:

   3:    public static int findNextValidInteger(String s) throws Exception {
   4:
   5:      // detect 1st digit after start of string
   6:      int beginIndex=0;
   7:      int endIndex=1;
   8:      int length=s.length();
   9:      while(!s.substring(beginIndex,endIndex).matches("\\d")) {
  10:        beginIndex++;
  11:        endIndex++;
  12:        if(endIndex>length) {
  13:          throw new Exception("No digit found.");
  14:        }
  15:      }
  16:      int i_startNumber= beginIndex;
  17:
  18:      // detect 1st non digit after start previously detected 1st digit   
  19:      beginIndex=i_startNumber;
  20:      endIndex=i_startNumber+1;
  21:      while(s.substring(beginIndex,endIndex).matches("\\d")) {
  22:        beginIndex++;
  23:        endIndex++;
  24:        if(endIndex>length) {
  25:          break;
  26:        }
  27:      }
  28:      int i_endNumber= beginIndex;
  29:
  30:      // return absolute value of integer
  31:      return Integer.valueOf(s.substring(i_startNumber, i_endNumber));
  32:    }
  33:
Can also be done the following way, but may take lot of resources if String
is very long and you only need the 1st Integer.
  35:
  36:    StringTokenizer str = new StringTokenizer("A 1965 Eric");
  37:
  38:    while(str.hasMoreElements()) {
  39:      System.out.println(str.nextElement());
  40:      int i = Integer.parseInt(str.nextElement());
  41:    }
  42: